The equation $x^{2} - 3 x + 5 = 0$ has real roots.

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Solution

The correct option is A 0
The given equation is $x^{2} - 3 x + 5 = 0$
Now, this is a quadratic equation.
If we compare with the standard form

$a x^{2} + b x + c = 0, a = 1, b = - 3 a n d c = 5.$

The discriminant
$b^{2} - 4 a c = (- 3)^{2} - 4 (1) (5) = 9 - 20 = - 11$ .

Since $b^{2} - 4 a c < 0$ , the equation will have no real roots.

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Similar questions

The number of real roots of the equation $x^{2} - 3 x + 5 = 0$ is:

f (x) {(f^{''} (x))}^{2} + f (x) f^{'} (x) f^{'''} (x) + {(f^{'} (x))}^{2} f^{''} (x) = 0

f (x) = 0

f (x) = 0

f^{'} (x) = 0

λ

(x^{2} + 3 x + 5)^{2} - (λ - 3) (x^{2} + 3 x + 4) (x^{2} + 3 x + 5) + (λ - 4) (x^{2} + 3 x + 4)^{2} = 0

x^{2} - 3 x + 5 = 0

x^{2} - 3 x + 5 = 0

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