1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XI
Mathematics
Range
The equation ...
Question
The equation
|
|
x
−
2
|
+
a
|
=
4
can have four distinct real solutions for
x
if
a
belongs to the interval
A
(
−
∞
,
−
4
)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(
−
∞
,
0
)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[
4
,
∞
)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
(
−
∞
,
−
4
)
|
|
x
−
2
|
+
a
|
=
4
⇒
|
x
−
2
|
+
a
=
±
4
⇒
|
x
−
2
|
=
±
4
−
a
For four real roots,
4
−
a
>
0
or
−
4
−
a
>
0
or,
a
∈
(
−
∞
,
−
4
)
Suggest Corrections
0
Similar questions
Q.
The equation
∣
|
x
−
1
|
+
a
∣
=
4
can have real solutions for
x
if
a
belongs to the interval
Q.
The equation
|
|
x
−
2
|
+
a
|
=
4
can have four distinct real solutions for
x
if
a
belongs to the interval
Q.
The equation
|
|
x
−
1
|
+
a
|
=
4
can have real solution for
x
if
a
belongs to the interval
Q.
The equation
|
x
+
1
|
|
x
−
1
|
=
a
2
−
2
a
−
3
can have real solution for
x
if
a
belongs to
Q.
The number of real roots of the equation
x
2
−
12
|
x
|
+
20
=
0
is
P
.
Then the values of
a
for which the equation
∣
∣
|
x
−
2
|
+
a
∣
∣
=
P
can have four distinct solutions, is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Explore more
Range
Standard XI Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app