wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation ||x2|+a|=4 can have four distinct real solutions for x if a belongs to the interval

A
(,4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(,0)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[4,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (,4)
||x2|+a|=4
|x2|+a=±4
|x2|=±4a
For four real roots,
4a>0 or 4a>0
or, a(,4)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon