Question

The equation $x^2-ax+b=0$ and $x^2-cx+d=0$ have a common root. The other root of $x^2-ax+b=0$ is the square of the other root of $x^2-cx+d=0$, then

• A. $b^2-bd=a{d}^2-c{d}^2$
• B. $b^2-bd=c{d}^2-a{d}^2$
• C. $b^2-b^{2}d=c^{2}d-a^{2}d$
• D. $b^2-b^{2}d=a^{2}d-c^{2}d$

Answer 1

The correct option is A $b^2-bd=a{d}^2-c{d}^2$

Option (a) is the correct answer. Check the video for the approach.