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Question

The equation x2px+q=0 p,qR has no real roots if

A
p2>4q
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B
p2<4q
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C
p2=4q
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D
None of these
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Solution

The correct option is B p2<4q
Nature of the roots for a quadratic equation a2+bx+c=0 can be determined by its Discriminant, D=b24ac
Here, D=p24q
Since, the roots are not real
Therefore,
D<0
=p24q<0
=p2<4q

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