The equation (x–2)(x+1)=(x–1)(x+3) is a quadratic equation.
True
False
(x–2)(x+1)=(x–1)(x+3)
x2+x–2x–2=x2+3x–x–3
x2+x–2x–2–x2–3x+x+3=0
−3x+1=0
Here, degree of equation is 1. Therefore, it is not a Quadratic Equation.