The equation $x^{2} + y^{2} + 4 x + 6 y + 13 = 0$ represents

Circle

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Pair of coincident straight lines

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Pair of concurrent straight lines

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Point

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Solution

The correct option is D Point
The given equation represents a Point circle ( $∴$ radius is zero).

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Similar questions

Q. The equation

x^{2} + y^{2} + 4 x + 6 y + 13 = 0

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x^{2} + y^{2} - 4 x - 4 y = 0

represents a circle with centre

(2, 2)

passing through the origin. Reason: The equation

x^{2} + y^{2} + 4 x + 6 y + 13 = 0

represents a point.

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x^{2} + y^{2} - 6 x - 4 y = 0

in the bisector of

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Q. The conic represented by the equation

x^{2} + y^{2} + 2 x y + 4 x - 6 y + 17 = 0

The angle between a pair of tangents drawn from a point P to the circle $x^{2} + y^{2} + 4 x - 6 y + 9 s i n^{2} α + 13 c o s^{2} α = 0 i s 2 α .$ The equation of the locus of the point P is

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The equation x2+y2+4x+6y+13=0 represents

The correct option is D PointThe given equation represents a Point circle (∴ radius is zero).

The equation $x^{2} + y^{2} + 4 x + 6 y + 13 = 0$ represents

The correct option is D Point
The given equation represents a Point circle ( $∴$ radius is zero).