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Byju's Answer
Standard XII
Mathematics
Descartes' Rule
The equation ...
Question
The equation
x
3
+
6
x
2
+
11
x
+
6
=
0
has
A
no negative roots
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B
no positive real roots
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C
no real roots
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D
1
positive and
2
negative roots
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E
1
negative and
2
positive roots
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Solution
The correct option is
B
no positive real roots
x
3
+
6
x
2
+
11
x
+
6
=
0
(
x
+
1
)
(
x
+
2
)
(
+
3
)
=
0
x
=
−
1
,
−
2
,
−
3
So, no positive real roots.
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0
Similar questions
Q.
Consider the cubic equation
x
3
−
4
x
2
+
x
+
6
=
0
Statement
1
:
Equation has
2
Positive real roots,
1
Negative real root
Statement
2
:
Equation has
1
Negative real root,
2
Imaginary roots.
Q.
If
α
and
β
are the roots of the equation
x
2
+
p
x
+
q
=
0
and
α
4
and
β
4
are the roots of the equation
x
2
−
r
x
+
s
=
0
, then the equation
x
2
−
4
q
x
+
2
q
2
−
r
=
0
has always:
Q.
If for the cubic equation
x
3
−
4
x
2
+
x
+
6
=
0
, the possible no. of positive real roots are
2
or
0
and the possible no. of negative real roots is
1
, then which of the following can be true?
Q.
Let a > 0, b > 0 and c > 0. Then both the roots of the equation
2
a
x
2
+
3
b
x
+
5
c
=
0
Q.
Let
f
(
x
)
=
x
13
+
x
11
+
x
9
+
x
7
+
x
5
+
x
3
+
x
+
19.
Then
f
(
x
)
=
0
has
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