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Question

The equation (x−3)9+(x−32)9+..(x−39)9=0 has

A
all real equation
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B
real root namely 3,32,..39
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C
one real & of imaginary roots
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D
None of these
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Solution

The correct option is C one real & of imaginary roots
Given equation is
Let f(x)=(x3)9+(x32)9+....+(x39)9=0

f(x)=9(x3)8+9(x32)8+.....+9(x39)8

since (x3)8>0

so f(x)>0
SO f(x) is increasing

So the Given equation only one and imaginary root.


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