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B
a parabola and two lines
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C
a hyparabola and two lines
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D
a line and a circle
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Solution
The correct option is A straight line Given equation is x3−x2y+x−y=0 ⇒x2(x−y)+(x−y)=0 ⇒(x2+1)(x−y)=0 Since x is real, x2+1=0 is not possible. Hence, x−y=0 or y=x. Thus the above expression represents a straight line.