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Question

The equation x + cosx = a has exactly one positive root. Complete set of values of 'a' is

A
(0, 1)
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B
(,1)
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C
(-1,1)
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D
(1,)
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E
(0,)
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Solution

The correct option is C (1,)
Let f(x) = x + cosx a
f(x)=1sinx0xϵR.
Thus f(x) is increasing in (,), as zero of f'(x) don't for an interval. f(0) = 1 a
For a positive root, 1a<0
a>1

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