The equation x + cosx = a has exactly one positive root. Complete set of values of 'a' is
A
(0, 1)
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B
(−∞,1)
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C
(-1,1)
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D
(1,∞)
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E
(0,∞)
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Solution
The correct option is C(1,∞) Let f(x) = x + cosx a ⇒f′(x)=1−sinx≥0∀xϵR. Thus f(x) is increasing in (−∞,∞), as zero of f'(x) don't for an interval. f(0) = 1 a For a positive root, 1−a<0 ⇒a>1