1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Higher Order Equations
The equation ...
Question
The equation
x
{
3
4
(
log
2
x
)
2
+
log
2
x
−
5
4
}
=
√
2
has
A
Atleast one real solution
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Exactly three real solution
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Exactly one irrational solution
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Complex roots
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
Exactly one irrational solution
It is given that
x
{
3
4
(
log
2
x
)
2
+
log
2
x
+
5
2
}
=
√
2
⇒
3
4
(
log
2
x
)
2
+
log
2
x
−
5
4
=
log
x
√
2
⇒
3
4
(
log
2
x
)
2
+
log
2
x
−
5
4
=
1
2
log
2
x
⇒
3
(
log
2
x
)
3
+
4
(
log
2
x
)
2
−
5
(
log
2
x
)
−
2
Put
log
2
x
=
y
Therefore,
3
y
3
+
4
y
3
−
5
y
−
2
=
0
⇒
y
=
1
,
−
2
,
−
1
3
⇒
log
2
x
=
1
,
−
2
,
−
1
3
⇒
x
=
2
,
1
2
1
/
3
,
1
4
Suggest Corrections
0
Similar questions
Q.
The equation
x
3
4
(
log
2
x
)
2
+
log
2
x
−
5
4
=
√
2
Q.
The equation
x
3
4
(
l
o
g
2
x
)
2
+
l
o
g
2
x
−
5
4
=
√
2
has
Q.
The equation
x
(
log
2
x
)
2
−
(
11
/
2
)
log
2
x
+
(
17
/
2
)
=
8
has
Q.
The equation,
x
(
3
4
(
log
2
x
)
2
+
log
2
x
−
5
4
)
=
√
2
has
Q.
If
x
1
,
x
2
,
x
3
are the three real solutions of the equation;
x
log
10
2
x
+
log
10
x
3
+
3
=
2
1
√
x
+
1
−
1
−
1
√
x
+
1
+
1
w
h
e
r
e
x
1
>
x
2
>
x
3
,
then
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
MATHEMATICS
Watch in App
Explore more
Higher Order Equations
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app