wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation x(log2x)2−(11/2)log2x+(17/2)=8 has

A
at least one real solution.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
exactly three real solutions.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
exactly one irrational solutions.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Exactly two real solutions.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A at least one real solution.
B exactly three real solutions.
C exactly one irrational solutions.
x(log2x)2(11/2)log2x+(17/2)=8
x(log2x)2(11/2)log2x+(17/2)=23
{(log2x)2(11/2)log2x+(17/2)}(log2x)=3
Let log2x=t, then
(t2112t+172)t=3
2t311t2+17t6=0
(t2)(t272t+32)=0
(t2)(t12)(t3)=0
t=12, 2, 3
log2x=12, 2, 3
x=2, 4, 8

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon