The correct options are
A at least one real solution.
B exactly three real solutions.
C exactly one irrational solutions.
x(log2x)2−(11/2)log2x+(17/2)=8
x(log2x)2−(11/2)log2x+(17/2)=23
{(log2x)2−(11/2)log2x+(17/2)}(log2x)=3
Let log2x=t, then
(t2−112t+172)t=3
2t3−11t2+17t−6=0
⇒(t−2)(t2−72t+32)=0
⇒(t−2)(t−12)(t−3)=0
⇒t=12, 2, 3
⇒log2x=12, 2, 3
x=√2, 4, 8