You visited us 1 times! Enjoying our articles? Unlock Full Access!

Constructing Perpendicular to a Line through a Point on the Line

The equation ...

Question

The equation $y = a x^{2} + b x + c$ is graphed in the standard $(x, y)$ coordinate plane below for real values of $a, b$ , and $c$ . When $y = 0$ , which of the following best describes the solutions for $x$ ?

2 distinct positive real solutions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 distinct negative real solutions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 positive real solution and 1 negative real solution

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 real solutions that are not distinct

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 distinct solutions that are not real

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1 positive real solution and 1 negative real solution
It is clear that parabola cuts the axis at two points one at positive x axis and one at negative x axis

Suggest Corrections

Similar questions

If a,b,c are distinct positive real numbers such that b(a+c) = 2ac then the roots a $x^{2}$ + 2bx + c = 0 are :

a x^{2} + b x + c = 0, a, b, c \in R

a c < 0,

If a, b, c are distinct positive real numbers such that b(a + c) = 2ac then the roots of $a x^{2} + b x + c = 0$ are

f (x) = a x^{2} + b x + c

a > 0, c < 0

b \in R

f (x) = 0

f (x) = a x^{2} + b x + c,

a > 0, b \in R, b \neq 0

f (x) = 0

c

a, b, c

a x^{2} + 2 b | x | - c = 0

Join BYJU'S Learning Program