The equation $z ¯ z + (2 - 3 i) z + (2 + 3 i) ¯ z + 4 = 0$ represents a circle of radius

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Solution

The correct option is B 3
Given, $z ¯ z + (2 - 3 i) z + (2 + 3 i) ¯ z + 4 = 0$
Here $a = 2 - 3 i, ¯ a = 2 + 3 i$ and $b = 4$
Hence radius
$= \sqrt{a ¯ a - b}$
$= \sqrt{(2 - 3 i) (2 + 3 i) - 4} = 3$

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