The equations x+2y+z=0,2x+4y+2z=1 have⋯⋯ solutions
A
0
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B
1
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C
8
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D
Infinity
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Solution
The correct option is A 0 Consider the first equation x+2y+z=0 ...(i) Consider the second equation 2x+4y+2z=1 ⇒x+2y+z=12 ...(ii) Hence both i and ii consist of a system of parallel planes. Therefore they never intersect and hence do not have any solution.