The equations of a pair of opposite sides of a parallelogram are $x^{2} - 5 x + 6 = 0$ and $y^{2} - 6 y + 5 = 0$ , then the equation of the diagonal having positive slope is

y = 4x+7

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y = 4x-7

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4x+y = 13

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4x+y = 15

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Solution

The correct option is B y = 4x-7
The sides are x = 2, x = 3, y = 1, y = 5
$∴$ vertices are A(2, 1), B(3, 1), C(3, 5), D(2, 5)
Equation of AC(+ve slope) is y = 4x - 7

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The equations of a pair of opposite sides of a parallelogram are x2–5x+6=0 and y2–6y+5=0, then the equation of the diagonal having positive slope is

The correct option is B y = 4x-7The sides are x = 2, x = 3, y = 1, y = 5 ∴ vertices are A(2, 1), B(3, 1), C(3, 5), D(2, 5) Equation of AC(+ve slope) is y = 4x - 7

The equations of a pair of opposite sides of a parallelogram are $x^{2} - 5 x + 6 = 0$ and $y^{2} - 6 y + 5 = 0$ , then the equation of the diagonal having positive slope is

The correct option is B y = 4x-7
The sides are x = 2, x = 3, y = 1, y = 5
$∴$ vertices are A(2, 1), B(3, 1), C(3, 5), D(2, 5)
Equation of AC(+ve slope) is y = 4x - 7