The equations of a pair of opposite sides of a parallelogram are x2 -5x+6 = 0 and y2 -6y+5=0, then the equation of the diagonal having positive slope is
y = 4x-7
The sides are x = 2, x = 3, y = 1, y =5
= vertices are A (2, 1), B(3, 1), C(3, 5), D(2, 5)
Eqn of AC(+ve slope) is y = 4x - 7