Question

The equations of line AB and line PQ are y = $-\frac{1}{2}x$ and y=2x respectively. Find the measure of angle $\angle$ BOQ which is formed by intersection of line AB and line PQ. (Point P and point A are in first and second quadrant respectively)

• A. ${60}^o$
• B. ${150}^o$
• C. ${90}^o$
• D. ${120}^o$

Answer 1

The correct option is C ${90}^o$

Given lines are $y=-\frac{1}{2}x$ ans $y=2x$.

Slope of first line $=m_1=-\frac{1}{2}$

Slope of second line $=m_2=2$

$m_1\times m_2=-\frac{1}{2}\times 2=-1$

Hence, option C is correct.