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Point Slope Form of a Line

The equations...

Question

The equations of one of the straight lines passing through the point $(0, 1)$ and is at a distance of $\frac{3}{5}$ units from the origin is

4 x + 3 y = 3

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- x + y = 1

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x + y = 1

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5 x + 4 y = 4

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Solution

The correct option is A $4 x + 3 y = 3$
For $m = - \frac{4}{3}$ then the equation will be
$3 (y - 1) = - 4 x$
or, $4 x + 3 y = 3$ .

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Similar questions

(0, 1)

\frac{3}{5}

x = y

1

(1, - 1)

x - y = 1

2 x + y = 3

\frac{\sqrt{3}}{2}

\sqrt{3} x \pm y - \sqrt{3} = 0

\sqrt{3} x \pm y + \sqrt{3} = 0

x \pm \sqrt{3} y - \sqrt{3} = 0

2

\sqrt{3} y^{2} - \sqrt{3} x^{2} - 2 x y = 0

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