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Question

The equations of tangent to the curve (xa)n+(yb)n=2at,(a,b) is 5.

A
xa+yb=2
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B
xa+yb=12
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C
xbya=2
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D
ax+by=2
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Solution

The correct option is A xa+yb=2
(xa)n+(yb)n=2at
n(xa)n11a+n(yb)n1yb=0
so, yb+1a=0 at (a,b)
so, y=ba
so, tangent equation
(yb)=ba(xa)
ayab=bx+ab
bx+ay=2ab
xa+yb=2

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