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Question

The equations of the circle which pass through the origin and makes intercepts of lengths 4 and 8 on the x and y-axes respectively are

A
x2+y2±4x±8y=0
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B
x2+y2±2x±4y=0
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C
x2+y2±8x±16y=0
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D
x2+y2±x±y=0
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Solution

The correct option is A x2+y2±4x±8y=0

Let S=x2+y20+2gx+2fy=0 be the equation of circle which passes through origin

C=(g,f),r=g2+f2

Given that it makes intercept of 4 with x-axis

4=2r2d2

Where d is distance between center and chord

2=g2+f2f2

g=±2

Similarly

2=g2+f2g2

g=±4

Equation of circle is

x2+y2±4x±8y=0


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