Question

The equations of the line passing through the point(1,2,-4) and perpendicularto the two lines $\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}$ and $\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}$, will be

• A.
  
• B.
  
• C.
  
• D. None of these

Answer 1

The correct option is A

Line passing through the point (1,2,-4) is $\frac{x-1}{l}=\frac{y-2}{m}=\frac{z+4}{n}$
Now, according to question, 3l-16m+7n=0 and 3l+8m-5n=0
Hence required line is, $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}$