The correct option is C (h2−r2)x−2rhy=0
The equation of any line through the origin (0, 0) is y = mx . . .(i)
If line (i) is tangent to the circle x2+y2−2rx−2hy+h2=0, then the length of perpendicular from center (r, h) on (i) is equal to the radius of the circle, i.e.,
|mr−h|√m2+1=√r2+h2−h2(mr−h)2=(m2+1)r20.m2+(2hr)m+(r2−h2)=0m=∞,h2−r22hr
Substituting these values in (i), we get the tangents as
x=0 and (h2−r2)x−2rhy=0