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Question

The equations of the tangents drawn from the origin to the circle x2+y2−2rx−2hy+h2=0 are

A
x=0
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B
y=0
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C
(h2r2)x2rhy=0
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D
(h2r2)x+2rhy=0
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Solution

The correct option is C (h2r2)x2rhy=0
The equation of any line through the origin (0, 0) is y = mx . . .(i)
If line (i) is tangent to the circle x2+y22rx2hy+h2=0, then the length of perpendicular from center (r, h) on (i) is equal to the radius of the circle, i.e.,
|mrh|m2+1=r2+h2h2(mrh)2=(m2+1)r20.m2+(2hr)m+(r2h2)=0m=,h2r22hr
Substituting these values in (i), we get the tangents as
x=0 and (h2r2)x2rhy=0

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