The correct option is B 4x – 3y – 24 = 0, 4x – 3y + 26 = 0
For the circle x2+y2 - 4x - 6y - 12 = 0, centre is (2, 3), radius = 5
Equation of a line parallel to 4x - 3y = 1 is 4x - 3y + k = 0
4x - 3y + k = 0 is a tangent to the circle |4(2)−3(3)+k|5 = 5 ⇒ |k−1| = 25 ⇒ k = 1 ± 25 ⇒
k = 26 or - 24.
∴ Required tangents are 4x - 3y + 26 = 0, 4x - 3y - 24 = 0