The equations of the tangnets to the ellipse 4x2+3y2=5 which are perpendicular to the line 3x−y+7=0 are :
A
2x−2y±√55=0
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B
2x+2y±√55=0
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C
2x+6y±√65=0
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D
2x+2y±√15=0
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Solution
The correct option is C2x+6y±√65=0 Slope of the tangents =−13 and for the given ellipse a2=54,b2=53 Equation of tangent in slope from is : y=mx±√a2m2+b2 ⇒y=−13x±√54×132+53 ∴6y+2x±√65=0