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Question

The equations of the tangnets to the ellipse 4x2+3y2=5 which are perpendicular to the line 3xy+7=0 are :

A
2x2y±55=0
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B
2x+2y±55=0
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C
2x+6y±65=0
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D
2x+2y±15=0
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Solution

The correct option is C 2x+6y±65=0
Slope of the tangents =13
and for the given ellipse a2=54,b2=53
Equation of tangent in slope from is :
y=mx±a2m2+b2
y=13x±54×132+53
6y+2x±65=0

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