Question

# The equations of three lines are given by : 15x-8y+1=0 ,12x+5y-3=0 and 21x-y-2=0 . Show that third line bisects angle between other two lines.

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Solution

## L1 : 15x - 8y + 1 = 0 L2 : -12x - 5y +3 = 0 Check: 15 (-12)+(-8) (-5) <0 ∴ Eqn. to acute angle bisector 15x−8y+117 = −12x−5y+313 ⇒195x-104y+13=-204x-85y+51 ⇒399x-19y-38=0 ⇒21x-y-2=0

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