The equilibrium concentrations of X,Y and YX2 are 4, 2 and 2 respectively for the equilibrium 2X(g)+Y(g)⇔YX2(g). The value of equilibrium constant kc is:
A
0.0625
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B
0.625
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C
0.0628
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D
0.628
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Solution
The correct option is B 0.0625 The equilibrium reaction is 2X(g)+Y(g)⇔YX2(g). The expression for the equilibrium constant is Kc=[YX2][X]2[Y]. Substitute values in the above expression. Kc=242×2=0.0625.