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Question

The equilibrium constant at 25 C for the reaction Fe2++Ag+Fe3++Ag is:
Given E0Ag+/Ag=0.7998 V and E0Fe3+/Fe2+=0.771 V, log 2 =0.30, log 3 = 0.48, 2.303RTF=0.06

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Solution

At equilibrium E(Cell)=0
According to Nernst equation,
E(Cell)=E0(Cell)2.303RTnF log Qc
0=(0.79980.771)0.061log Kc So, log Kc=0.48Kc=3

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