The equilibrium constant at 25oC for the process- Co 3- aq-6 NH 3 aq- Co NH 3 6 - 3- aq- is 2- 10 7Calculate the value of - G o at 25oC- R-8-314J K -1 mol -1

We know that Δ G ^ o = 2.303RTlog K _ c Given, K _ c =2× 10 ^ 7 ,T=298K,R=8.314J K ^ 1 mol ^ 1 Thus, from the above equation Δ G ^ o = 2.303× 8. ...

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Gibbs Free Energy & Spontaneity

The equilibri...

Question

The equilibrium constant at $25^{o} C$ for the process:
${C o}^{3 +} (a q .) + 6 {N H}_{3} (a q .) ⇌ {[C o {({N H}_{3})}_{6}]}^{3 +} (a q .)$ is $2 \times 10^{7}$
Calculate the value of $Δ G^{o}$ at $25^{o} C$ . $(R = 8.314 J K^{- 1} {m o l}^{- 1})$

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25^{o} C

C o^{3 +} (a q .) + 6 N H_{3} (a q .) ⇌ [C o (N H_{3})_{6}]^{3 +} (a q .) i s 2 \times 10^{7} .

△ G^{o} (i n k J / m o l) a t 25^{o} C . (R = 8.314 J K^{- 1} m o l^{- 1})

C u (s) + 2 {A g}^{+} (a q .) ⇌ {C u}^{2 +} (a q) + 2 A g (s)

25^{o} C

E_{c e l l}^{o} = 0.47 v o l t, R = 8.314 J K^{- 1} {m o l}^{- 1}, F = 96500 c o u l o m b

Δ G^{o} = + 63.3 k J

K_{s p}

{A g}_{2} {C O}_{3} (s)

25^{o} C

{A g}_{2} {C O}_{3} (s) ⇋ {A g}^{+} (a q .) + {C O}_{3}^{2 -} (a q .)

Δ G^{o} = + 63.3 k J

K_{s p}

A g_{2} C O_{3} (s)

25^{o} C

A g_{2} C O_{3} (g) ⇌ 2 A g^{+} (a q) + C O_{3}^{2 -} (a q)

(R = 8.314 J K^{- 1} m o l^{- 1})

K_{p} = 1.7 \times 10^{7}

25^{o} C

{A g}^{+} (a q .) + 2 {N H}_{3} (g) ⇌ {[A g {({N H}_{3})}_{2}]}^{+}

Δ G^{o}

k J

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