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Question
The equilibrium constant for a reaction is 10. ΔG∘ will be (R=8JK−1mol−1,T=300K)
The equilibrium constant for a reaction is 10. ΔG∘ will be (R=8JK−1mol−1,T=300K)
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Solution
The correct option is B
ΔG∘=−2.303RTlogk=−2.303RT×8×300log10=−2.303×8×300=−5527Jmol−1=−5.527kJmol−1
ΔG∘=−2.303RTlogk=−2.303RT×8×300log10=−2.303×8×300=−5527Jmol−1=−5.527kJmol−1
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