Question

The equilibrium constant for a reaction is 10. $\Delta G^{\circ }$ will be $(R=8J{K}^{-1}mo{l}^{-1},T=300K)$

• A. $-5527kJmo{l}^{-1}$
• B. $-5.527kJmo{l}^{-1}$
• C. $-55.27kJmo{l}^{-1}$
• D. $+5.527kJmo{l}^{-1}$

Answer 1

The correct option is B $-5.527kJmo{l}^{-1}$

$\Delta G^{\circ }=-2.303RTlogk=-2.303RT\times 8\times 300log10=-2.303\times 8\times 300=-5527Jmo{l}^{-1}=-5.527kJmo{l}^{-1}$