Question

The equilibrium constant for a reaction is 10. $\Delta G^{\circ }$ will be:
$\left(\text{R= 8 J/Kmol, T = 300 K}\right)$

• A. $-5527\text{kJ/mol}$
• B. $-5.527\text{kJ/mol}$
• C. $-55.27\text{kJ/mol}$
• D. $+5.527\text{kJ/mol}$

Answer 1

The correct option is B $-5.527\text{kJ/mol}$

$\Delta G=-2.303\text{RT}\text{log K}$
$=-2.303\times 8\times 300\times \text{log 10}$
$=-2.303\times 8\times 300=-5.527\text{kJ/mol}$