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The equilibri...

Question

The equilibrium constant for reaction $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$ is $K$ , What is the equilibrium constant for reaction,
$\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$

A

\frac{1}{2} K

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B

K^{2}

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C

\sqrt{K}

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D

K

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Solution

The correct option is C $\sqrt{K}$
If the equilibrium constant for $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$ is $K$ , the equilibrium constant for
$\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$
will be $K^{'} = \sqrt{K}$
$K = \frac{[N O]^{2}}{[N_{2}] [O_{2}]}$
$K^{'} = \frac{[N O]}{\sqrt{[N_{2}] [O_{2}]}} = \sqrt{\frac{[N O]^{2}}{[N_{2}] [O_{2}]}} = \sqrt{K}$

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Similar questions

Q. If the equilibrium constant for

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

K

, the equilibrium constant for

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)

Q. The equilibrium constant for the reactions

N_{2 (g)} + O_{2_{(} g)} ⇋ 2 N O_{(g)}

N O_{(g)} ⇋ \frac{1}{2} N_{2 (g)} + \frac{1}{2} O_{2_{(} g)}

k^{1}

, the relation between k and

k^{1}

K_{1}

K_{2}

are equilibrium constant for reactions (1) & (2)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g)

K_{1}

K_{2}

are equilibrium constants for reaction (i) and (ii)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g)

.....(ii)
Then :

K_{1}

K_{2}

are equilibrium constant for reactions (1) and (2)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g) . . . . . . (1)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) . . . . . . . . . (2)

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