The equilibrium constant for the following reaction is 49 at 450- C- If 0-22 mol of I 2- 0-22 mol of H 2 and 0-66 mol of HI were put in a evacuated 1 litre container- H 2- I 2- 2 HIThen- the correct statement will be-A- Reaction will proceed in forward direction until equilibrium is established-B- Reaction will proceed in backward direction until equilibrium is established-C- Reaction is already at equilibrium-D- None of the above

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Characteristics of Equilibrium Constant

The equilibri...

Question

The equilibrium constant for the following reaction is 49 at $450^{o} C .$ If $0.22 m o l$ of $I_{2}$ , $0.22 m o l$ of $H_{2}$ and $0.66 m o l$ of $H I$ were put in a evacuated 1 litre container.
$H_{2} + I_{2} ⇌ 2 H I$
Then, the correct statement will be:

Reaction will proceed in forward direction until equilibrium is established.

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Reaction will proceed in backward direction until equilibrium is established.

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Reaction is already at equilibrium.

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None of the above

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Solution

The correct option is A Reaction will proceed in forward direction until equilibrium is established.
Given, $n_{H_{2}} = 0.22, n_{I_{2}} = 0.2, n_{H I} = 0.66 V = 1 L$

$∴ [H_{2}] = 0.22, [I_{2}] = 0.22, [H I] = 0.66$

The concentration given in question are not necessarily the equilibrium concentrations.
Calculating reaction quotient $Q_{c}$ from these concentrations :

The reaction is
$H_{2} + I_{2} ⇌ 2 H I$

For this reaction, $Q_{c} = \frac{[H I]^{2}}{[H_{2}] [I_{2}]}$

putting the value,
$Q_{c} = \frac{(0.66)^{2}}{(0.22) (0.22)}$
$Q_{c} = 9.0$ but $K_{c} = 49$ (Given), which is greater than $Q_{c}$

i.e. $K_{c} > Q_{c}$

Hence, the reaction will move in forward direction.

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Characteristics of Equilibrium Constant

Standard XII Chemistry

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The equilibrium constant for the following reaction is 49 at 450oC. If 0.22 mol of I2, 0.22 mol of H2 and 0.66 mol of HI were put in a evacuated 1 litre container. H2+I2⇌2HI Then, the correct statement will be:

The equilibrium constant for the following reaction is 49 at $450^{o} C .$ If $0.22 m o l$ of $I_{2}$ , $0.22 m o l$ of $H_{2}$ and $0.66 m o l$ of $H I$ were put in a evacuated 1 litre container.
$H_{2} + I_{2} ⇌ 2 H I$
Then, the correct statement will be: