The equilibrium constant for the given reaction is 100. N2(g)+2O2(g)⇌2NO2(g) What is the equilibrium constant for the reaction given below? NO2(g)⇌12N2(g)+O2(g).
A
10
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B
1
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C
0.1
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D
0.01
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Solution
The correct option is B0.1 N2+2O2⇌2NO2 K1=[NO2]2[N2][O2]2 or 100=[NO2]2[N2][O2]2....(i) Again, [NO2]⇌12N2+O2 K2=[N2]1/2[O2][NO2] or K22=[N2][O2]2[NO2]2....(ii) On multiplying Eqs. (i) and (ii), we get 100×K22=1 or K22=1100 K2=110=0.1.