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Derivation of Kp and Kc

The equilibri...

Question

The equilibrium constant for the reaction: $2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}$ is 5. If the equilibrium constant mixture contains equal moles of $S O_{3}$ and $S O_{2}$ , the equilibrium partial pressure of $O_{2}$ gas is:

A

0.2 atm

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B

2 atm

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C

0.02 atm

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D

0.04 atm

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Solution

The correct option is B 0.2 atm
$2 S O_{2} + O_{2} ⇌ 2 S O_{3}$
$P_{S O_{3}} = P_{S O_{2}}$
$K_{p} = \frac{(P_{S O_{3}})^{2}}{(P_{S O_{2}})^{2} P_{O_{2}}} = 5$
$= \frac{1}{P_{O_{2}}} = 5$
$P_{O_{2}} = \frac{1}{5} = 0.2$

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Similar questions

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