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Standard XII

Chemistry

Introduction

The equilibri...

Question

The equilibrium constant for the reaction $A_{2} + B_{2} ⇌ 2 A B$ is 20 at 500 K .The equilibrium constant for the reaction $2 A B_{(g)} ⇌ A_{2 (g)} + B_{2 (g)}$ would be

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0.5

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0.05

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Solution

The correct option is C
0.05

$K_{2} = \frac{1}{K_{1}} = \frac{1}{20} = 5 \times 10^{- 2}$
(or)
0.05

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Similar questions

The equilibrium constant for the reaction $A_{2} + B_{2} ⇌ 2 A B$ is 20 at 500 K .The equilibrium constant for the reaction $2 A B_{(g)} ⇌ A_{2 (g)} + B_{2 (g)}$ would be

Q. The equilibrium constant of the reaction,

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g)

100^{o} C

16.

Initially equal moles of

A_{2} & B_{2}

are taken in

2 L

container. Then find mole % of

A_{2}

in equilibrium mixture.

Q. If the equilibrium constant for reaction

A_{2} + B_{2} ⇌ 2 A B

K

, then equilibrium constant for

\frac{1}{2} A_{2} + \frac{1}{2} B_{2} ⇌ A B

\sqrt{K}

Q. If the equilibrium constant for the reaction

2 A B ⇌ A_{2} + B_{2}

49

, what is the equilibrium constant for

A B ⇌ \frac{1}{2} A_{2} + \frac{1}{2} B_{2}

Q. If the equilibrium constant for the reaction

2 A B ⇋ A_{2} + B_{2}

36

, then what is the equilibrium constant for

A B ⇋ \frac{1}{2} A_{2} + \frac{1}{2} B_{2}

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The equilibrium constant for the reaction A2+B2⇌2AB is 20 at 500 K .The equilibrium constant for the reaction 2AB(g)⇌A2(g)+B2(g) would be

The correct option is C 0.05 K2=1K1=120=5×10−2 (or) 0.05

The equilibrium constant for the reaction $A_{2} + B_{2} ⇌ 2 A B$ is 20 at 500 K .The equilibrium constant for the reaction $2 A B_{(g)} ⇌ A_{2 (g)} + B_{2 (g)}$ would be

The correct option is C
0.05

$K_{2} = \frac{1}{K_{1}} = \frac{1}{20} = 5 \times 10^{- 2}$
(or)
0.05