The equilibrium constant for the reaction $A_{2} + B_{2} ⇌ 2 A B$ is 20 at 500 K .The equilibrium constant for the reaction $2 A B_{(g)} ⇌ A_{2 (g)} + B_{2 (g)}$ would be

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.05

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
0.05

$K_{2} = \frac{1}{K_{1}} = \frac{1}{20} = 5 \times 10^{- 2}$
(or)
0.05

Suggest Corrections

Similar questions

The equilibrium constant for the reaction $A_{2} + B_{2} ⇌ 2 A B$ is 20 at 500 K .The equilibrium constant for the reaction $2 A B_{(g)} ⇌ A_{2 (g)} + B_{2 (g)}$ would be

The equilibrium constant $k_{c}$ of the reaction $A_{2}$ (g) + $B_{2}$ (g) $⇌$ 2AB (g) is 50. If 1 mol of $A_{2}$ and 2 mol of $B_{2}$ are mixed, the amount of AB at equilibrium would be: