The equilibrium constant for the reaction: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq)is 140 at 298 K. The Equilibrium constant for the reaction: 2Fe3+(aq)+2SCN−(aq)⇌2FeSCN2+(aq)is:
A
280
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B
140
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C
19600
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D
70
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Solution
The correct option is C 19600 K=[FeSCN2+][Fe3+][SCN−]=140,K1=[FeSCN2+]2[Fe3+]2[SCN−]2=(140)2=19600