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Question

The equilibrium constant for the reaction given below is 2.0×107 at 300 K. Calculate the standard entropy change if H=28.40 kJmol1 for the reaction:
PCl5(g)PCl3(g)+Cl2(g)

A
33.6 Jmol1K1
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B
33.6 Jmol1K1
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C
43.6 Jmol1K1
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D
43.6 Jmol1K1
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Solution

The correct option is A 33.6 Jmol1K1
K=2.0×107T=300KH=28.4kJmol1G=2.303 RT logk=2.303×8.314×103×300×log(2×107)=5.744(log27)=5.744(0.30107)=38.48kJ
From G=HTSTHGS=HGT=28.438.48300=0.0336 kJ mol1
or S=33.6 J mol1K1

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