Question

The equilibrium constant for the reaction is 0.50. Assuming that the reaction proceeds by one-step mechanism. Find the rate constant of reverse reaction ?

• A. $0.294$ $h{r}^{-1}$
• B. $0.588$ $h{r}^{-1}$
• C. $0.123$ $h{r}^{-1}$
• D. $0.117$ $h{r}^{-1}$

Answer 1

The correct option is B $0.588$ $h{r}^{-1}$

$X\left(g\right)\rightleftharpoons Y\left(g\right)+Z\left(g\right)$
$k_{eq}=\frac{k_f}{k_b}$
$\Rightarrow K_b=\frac{0.294h{r}^{-1}}{0.50}=0.588h{r}^{-1}$