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Byju's Answer
Standard XII
Chemistry
Characteristics of Equilibrium Constant
The equilibri...
Question
The equilibrium constant for the reaction,
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
, at
715
K
is
6.0
×
10
−
2
M
−
2
. If in a particular reaction, there are
0.25
m
o
l
L
−
1
of
H
2
and
0.06
m
o
l
L
−
1
of
N
H
3
present, calculate the concentration of
N
2
at equilibrium.
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Solution
The given reaction is :-
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
⇒
K
C
=
[
N
H
3
]
2
[
N
2
]
[
H
2
]
3
Now,
[
H
2
]
=
0.25
M
;
[
N
H
3
]
=
0.06
M
K
C
=
6
×
10
−
2
M
−
2
⇒
6
×
10
−
2
=
0.06
×
0.06
(
0.25
)
3
×
[
N
2
]
⇒
[
N
2
]
=
0.06
×
0.06
0.06
×
0.25
×
0.25
×
0.25
=
3.84
M
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0
Similar questions
Q.
Calculate the equilibrium constant
(
K
c
)
for the formation of
N
H
3
in the following reaction:
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
At equilibrium, the concentration of
N
H
3
,
H
2
and
N
2
are
1.2
×
10
−
2
,
3.0
×
10
−
2
and
1.5
×
10
−
2
M
respectively.
Q.
The following concentration were obtained for the formation of
N
H
3
form
N
2
and
H
2
at equilibrium for the reaction
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
[
N
2
]
=
1.5
×
10
−
2
M
[
H
2
]
=
3.0
×
10
−
2
M
[
N
H
3
]
=
1.2
×
10
−
2
M
Calculate equilibrium constant.
Q.
The following concentration were obtained for the formation of
N
H
3
form
N
2
and
H
2
at equilibrium for the reaction
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
[
N
2
]
=
1.5
×
10
−
2
M
[
H
2
]
=
3.0
×
10
−
2
M
[
N
H
3
]
=
1.2
×
10
−
2
M
Calculate equilibrium constant.
Q.
Assertion :For reaction
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
Unit of
K
C
=
L
2
m
o
l
−
2
Reason: For the reaction
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
, Equilibrium constant
K
C
=
[
N
H
3
]
2
[
N
2
]
[
H
2
]
3
Q.
The equilibrium constant
K
p
for the reaction
N
2
(g) + 3
H
2
(g)
⇋
2
N
H
3
(g) is:
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