The equilibrium constant for the reaction
$P + Q ⇌ R + S; K_{c} = 0.2$
hence, the equilibrium constant for the following reaction will be:
$R + S ⇌ P + Q$

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Solution

The equilibrium constant for the reaction
$P + Q ⇌ R + S; K_{c} = 0.2$ .....(1)
hence, the equilibrium constant for the following reaction will be $5$
$R + S ⇌ P + Q; K_{c}^{'}$ .....(2)
When reaction (1) is reversed, reaction (2) is obtained.
$K_{c}^{'} = \frac{1}{K_{c}}$
$K_{c}^{'} = \frac{1}{0.2} = 5$

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