The equilibrium constant $K_{c}$ for the reaction:
$C u (s) + 2 A g^{+} (a q .) ⇌ C u^{2 +} (a q .) + 2 A g (s) (E_{c e l l}^{\circ} = 0.46 V)$ will be:

a n t i l o g 15.6

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a n t i l o g 2.5

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a n t i l o g 1.5

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a n t i l o g 12.2

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Solution

The correct option is A $a n t i l o g 15.6$
$C u_{(s)} + 2 A g_{(a q)}^{+} ⇌ C u_{(a q)}^{2 +} + 2 A g_{(s)} (E_{c e l l}^{\circ} = 0.46 V)$
At equilibrium;
$E_{c e l l}^{\circ} = \frac{0.059}{n} log K$
$⟹ 0.46 = \frac{0.059}{2} log K ⟶ log K = 15.59$
$∴$ $K = a n t i l o g$ $15.6$

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Similar questions

2 A g^{+} (a q .) + C u (s) ⇌ C u^{2 +} (a q .) + 2 A g (s) (E_{c e l l}^{\circ} = + 0.46 V)

C u (s) + 2 {A g}^{+} (a q) \to {C u}^{2 +} (A q) + 2 A g (s)

(K)

E_{c e l l}^{\circ} = 0.46 V

Calculate the equilibrium constant of the reaction.
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$ , $E_{c e l l}^{⊖} = 0.46 V$

C u (s) + 2 {A g}^{+} (a q) ⟶ {C u}^{2 +} (a q) + 2 A g (s)

E^{o} = 0.46 V

298 K

C u (s) + 2 A g^{+} (a q) ⇌ C u^{2 +} (a q) + 2 A g (s)

E^{\circ} = 0.46 V

298 K

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