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Question

The equilibrium constant, Kc for the reaction
H2(g)+I2(g)2HI(g)
is 56.8 at 800K. When the mixture was analysed, it was found to contain 0.316mol/L HI at 800K. What are the concentrations of H2 and I2 at equilibrium? (Assume that initial concentrations of H2 and I2 were the same)

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Solution

The equilibrium concentration of HI is 0.316 mol/L HI
Let x M be the equilibrium concentrations of hydrogen and iodine each.
The equilibrium constant Kc=[HI]2[H2][I2]
56.8=[0.316]2x×x
0.00176=x2
[H2]=[I2]=x=0.0419mol L1

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