Question

The equilibrium constant $K_c$ is ${10}^2$ for the reaction $AB+C\leftrightharpoons AC+B$. The rate constant for the forward reaction K is ${10}^6$, the rate constant of backward reaction is :

• A. ${10}^4$
• B. ${10}^8$
• C. ${10}^{-4}$
• D. ${10}^{-2}$

Answer 1

The correct option is A ${10}^4$

$K_c=\frac{K_f}{K_b}$

${10}^2=\frac{{10}^6}{K_b}$

$\therefore$$K_b=\frac{{10}^6}{{10}^2}={10}^4$