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The equilibri...

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The equilibrium constant (K) for the reaction,2SO2(g)+O2(g)2S03(g) at 1000 K is 3.5 atmWhat would be the partial pressure of oxygen gas,if the equilibrium is found to have equal moles ofSO2 and SO3?

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Q. The equilibrium constant

K_{p}

for the reaction

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

1000 K

is 3.5. What would be the partial pressure of

O_{2}

gas with equal moles of

S O_{2}

S O_{3}

at equilibrium?

Q. The equilibrium constant for the reaction:

2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

is 5. If the equilibrium constant mixture contains equal moles of

S O_{3}

S O_{2}

, the equilibrium partial pressure of

O_{2}

Q. The equilibrium constant

K_{p}

of the reaction:

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

is 900 atm at 800 K. A mixture containing

S O_{3}

O_{2}

having initial partial pressure of 1 and 2 atm. respectively is heated at constant volume to equilibriate. Calculate the partial pressure of

O_{2}

Q. The equilibrium constant

K_{p}

for the reaction,

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

900 {a t m}^{- 1}

800 K

. A mixture containing

{S O}_{3}

O_{2}

having initial partial pressure of

1

2 a t m

respectively is heated at constant volume to equilibriate. Calculate the partial pressure of each gas at

800 K

at equilibrium.

Q. In the equilibrium

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

, the partial pressures of

S O_{2}, O_{2}

S O_{3}

0.662, 0.101

0.331 a t m

respectively. What would be the partial pressure of oxygen so that the equilibrium concentration of

S O_{2}

S O_{3}

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