1
Question
The equilibrium constant of a 2 electron redox reaction at 298 K is 3.8×10–3. The cell potential Eo (in V) and the free energy change △Go (in kJ mol–1) for this equilibrium respectively, are:
The equilibrium constant of a 2 electron redox reaction at 298 K is 3.8×10–3. The cell potential Eo (in V) and the free energy change △Go (in kJ mol–1) for this equilibrium respectively, are:
Open in App
Solution
The correct option is B -0.071, 13.8
ΔGo=−RTlnK=−8.314 J mol−1 K−1×298 K ×2.303 log(3.8×10−3)=13.809 kJ mol−1ΔGo=−nFEo13809=−2×96500 EoEo=−0.071 V
ΔGo=−RTlnK=−8.314 J mol−1 K−1×298 K ×2.303 log(3.8×10−3)=13.809 kJ mol−1ΔGo=−nFEo13809=−2×96500 EoEo=−0.071 V
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
