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Rate of Reaction

The equilibri...

Question

The equilibrium constant of a reaction is $20$ . At equilibrium, the rate constant of forward reaction is $10$ . The rate constant for backward reaction is :

A

0.5

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B

2

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C

10

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D

200

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Solution

The correct option is A $0.5$
As we know,
$K_{c} = \frac{K_{f}}{K_{b}}$
$∴ 20 = \frac{10}{K_{b}}$
$∴ K_{b} = \frac{1}{2} = 0.5$

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