Question

The equilibrium constant of a reaction is $20$. At equilibrium, the rate constant of forward reaction is $10$. The rate constant for backward reaction is :

• A. $0.5$
• B. $2$
• C. $10$
• D. $200$

Answer 1

The correct option is A $0.5$

As we know,
$K_c=\frac{K_f}{K_b}$
$\therefore 20=\frac{10}{K_b}$
$\therefore K_b=\frac{1}{2}=0.5$